Which of the following metals will not react with a solution of $CuSO_4$?

Depict the galvanic cell in which the reaction $Zn_{(s)} + 2Ag_{(aq)}^{+} \to Zn_{(aq)}^{2+} + 2Ag_{(s)}$ takes place. Further show:
$(i)$ Which electrode is negatively charged?
$(ii)$ The carriers of the current in the cell.
$(iii)$ Individual reaction at each electrode.

The limiting molar conductivity $\Lambda^o$ for $NaCl$,$KBr$ and $KCl$ are $126$,$152$ and $150 \ S \ cm^2 \ mol^{-1}$ respectively. The $\Lambda^o$ for $NaBr$ is (in $S \ cm^2 \ mol^{-1}$).

Assertion : For the Daniel cell,$Zn|Zn^{2+} || Cu^{2+}|Cu$ with $E_{cell} = 1.1 \ V$,the application of an opposite potential greater than $1.1 \ V$ results in the flow of electrons from cathode to anode.
Reason : $Zn$ is deposited at the anode,and $Cu$ is deposited at the cathode.

In the reaction $Cu_{(s)} + 2Ag^{+}_{(aq)} \to Cu^{2+}_{(aq)} + 2Ag_{(s)}$,the reduction half-cell reaction is:

Assertion: The cell potential of a mercury cell is $1.35 \ V$,which remains constant.
Reason: In a mercury cell,the electrolyte is a paste of $KOH$ and $ZnO$.