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(D) To determine the number of unpaired electrons,we write the electronic configuration for each ion:$Fe^{2+}$ $(Z=26)$: $[Ar] 3d^6$. Unpaired electro

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$Mn^{2+}$

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(D) To determine the number of unpaired electrons,we write the electronic configuration for each ion:$Fe^{2+}$ $(Z=26)$: $[Ar] 3d^6$. Unpaired electrons = $4$.$Co^{2+}$ $(Z=27)$: $[Ar] 3d^7$. Unpaired electrons = $3$.$Ni^{2+}$ $(Z=28)$: $[Ar] 3d^8$. Unpaired electrons = $2$.$Mn^{2+}$ $(Z=25)$: $[Ar] 3d^5$. Unpaired electrons = $5$.Thus,$Mn^{2+}$ has the maximum number of unpaired electrons $(5)$.

Which of the following metal ions will have the maximum number of unpaired electrons?

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