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(C) The stability of an isotope is often related to its neutron-to-proton ratio ($n/p$ ratio).For $_{30}Zn^{64}$,the number of protons $(p)$ is $30$ a

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$_{30}Zn^{64}$

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(C) The stability of an isotope is often related to its neutron-to-proton ratio ($n/p$ ratio).For $_{30}Zn^{64}$,the number of protons $(p)$ is $30$ and the number of neutrons $(n)$ is $64 - 30 = 34$.The $n/p$ ratio is $\frac{34}{30} \approx 1.13$.For $_{30}Zn^{66}$,$n = 36$,so $n/p = \frac{36}{30} = 1.2$.For $_{30}Zn^{71}$,$n = 41$,so $n/p = \frac{41}{30} \approx 1.37$.Since $_{30}Zn^{64}$ has the lowest $n/p$ ratio among the given options and is a naturally occurring stable isotope of Zinc,it is the most stable.

Which of the following isotopes is likely to be most stable?

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