Which of the following is the strongest base?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The basicity of amines depends on the availability of the lone pair of electrons on the nitrogen atom for protonation.In aniline $(C_6H_5NH_2)$,$N

Vedclass · Accepted Answer

Benzylamine

Vedclass · Answer

(D) The basicity of amines depends on the availability of the lone pair of electrons on the nitrogen atom for protonation.In aniline $(C_6H_5NH_2)$,$N$-methylaniline $(C_6H_5NHCH_3)$,and $o$-toluidine $(2-CH_3C_6H_4NH_2)$,the lone pair on the nitrogen atom is in conjugation with the benzene ring,which decreases its availability for protonation.In benzylamine $(C_6H_5CH_2NH_2)$,the nitrogen atom is attached to a $CH_2$ group,not directly to the benzene ring. Therefore,the lone pair on the nitrogen atom is not involved in resonance with the benzene ring,making it more available for protonation.Thus,benzylamine is the strongest base among the given options.

Similar Questions

If $meta$-nitroaniline is chlorinated,the major product is:

$CH_3CH_2Br$ $\xrightarrow{AgCN} A$ $\xrightarrow{H_2, Ni} B$. The final product $(B)$ is

$C_6H_5CONHCH_3$ can be converted into $C_6H_5CH_2NHCH_3$ by

Nitrobenzene on reduction with zinc and $NH_4Cl$ gives:

The reaction of $CH_3NH_2$ with $CH_3MgX$ yields ...........

Vedclass Test Series

Exam Paper Generator

Online Exam Module