Which of the following is the correct order f | vedclass

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(C) The correct order of bond angle is $H_3Te^{+} < H_3Se^{+} < H_3S^{+} < H_3O^{+}$.Explanation:$(a)$ In $NH_3$ group hydrides,as the electronegativi

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$H_3Te^{+} < H_3Se^{+} < H_3S^{+} < H_3O^{+}$

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(C) The correct order of bond angle is $H_3Te^{+} Explanation:$(a)$ In $NH_3$ group hydrides,as the electronegativity of the central atom decreases,the bond angle decreases: $NH_3 > PH_3 > AsH_3 > SbH_3$.$(b)$ In $OF_2$ and $H_2O$,the bond angle is affected by the electronegativity of the surrounding atoms. The correct order is $OF_2 $(c)$ In $H_3X^{+}$ species,as the electronegativity of the central atom $X$ increases,the bond angle increases. Thus,$H_3Te^{+} $(d)$ In $BX_3$ molecules,the bond angle is $120^{\circ}$ for all due to $sp^2$ hybridization,so $BF_3 = BCl_3 = BBr_3 = BI_3$.

Which of the following is the correct order for increasing bond angle?

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