Which of the following is the strongest acid?

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Question

(A) The acidic strength of an acid is inversely proportional to the basic strength of its conjugate base. $1$. The conjugate base of $NH_4^+$ is $NH_3

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$NH_4^+$

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(A) The acidic strength of an acid is inversely proportional to the basic strength of its conjugate base. $1$. The conjugate base of $NH_4^+$ is $NH_3$. $2$. The conjugate base of the ion in option $B$ is $1,2,3,4$-tetrahydroisoquinoline. $3$. The conjugate base of the ion in option $C$ is $1,2,3,4$-tetrahydroquinoline. $4$. The conjugate base of the ion in option $D$ is piperidine. Among these,$NH_3$ is the least basic because it lacks the electron-donating alkyl groups present in the other cyclic amines. Since $NH_3$ is the weakest base,its conjugate acid $NH_4^+$ is the strongest acid.

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Identify $X$ and $Y$ in the following reaction: ${C_6H_5NH_2}$ $\xrightarrow[0^{\circ} - 5^{\circ}C]{NaNO_2 + 2HCl} X$ $\xrightarrow[H_2O]{HNO_2} Y + N_2 + HCl$

$A$ $\xrightarrow{H_2NOH} B$ $\xrightarrow{\text{reduction}} C$ $\xrightarrow{NOCl} CH_3CH_2Cl$. What are $A$ and $C$ in the given reaction sequence?

Consider the following statements:
Statement-$I$: $CH_3NH_2$ is more basic than $NH_3$,but $C_6H_5NH_2$ is less basic than $NH_3$.
Statement-$II$: The order of basic strength of ethyl-substituted amines in the aqueous phase follows the order $(C_2H_5)_2NH > (C_2H_5)_3N > C_2H_5NH_2$.

Which of the following is the most basic compound?

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