(A) The oxidation of $prop-1-ene$ $(CH_3-CH=CH_2)$ with acidic $KMnO_4$ leads to the cleavage of the double bond. The terminal $CH_2$ group is oxidize

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(A) The oxidation of $prop-1-ene$ $(CH_3-CH=CH_2)$ with acidic $KMnO_4$ leads to the cleavage of the double bond. The terminal $CH_2$ group is oxidized to $CO_2$ and $H_2O$,while the $CH_3-CH=$ group is oxidized to ethanoic acid $(CH_3COOH)$. The reaction is: $CH_3-CH=CH_2 + [O] \xrightarrow{acidic \ KMnO_4} CH_3COOH + CO_2 + H_2O$.

Class 11 Chemistry Hydrocarbons Alkene

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Which of the following is obtained on oxidation of $prop-1-ene$ with acidic $KMnO_4$?

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A
Ethanoic acid
B
Propanol
C
Propanoic acid
D
Propanone

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Given the enthalpy of hydrogenation of these compounds will be in the order:

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For the given reaction:
(Cyclohexyl)-$CH$=$CH$-(Cyclohexyl) $\xrightarrow{KMnO_4/H^+}$ '$P$' (major product)
'$P$' is:

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Write the main product of the given reactions:
$(1)$ $CH_3CH = CHCH_3 + HBr \to$
$(2)$ $CH_3-C(CH_3)=CH_2 + HBr \to$

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Which of the following is obtained on oxidation of $prop-1-ene$ with acidic $KMnO_4$?

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Alkene $(x) \xrightarrow[\Delta]{KMnO_4/H^+} \text{Products}$. Identify the alkene $(x)$ from the given products:

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For the given reaction:(Cyclohexyl)-$CH$=$CH$-(Cyclohexyl) $\xrightarrow{KMnO_4/H^+}$ '$P$' (major product)'$P$' is:

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For the given reaction:
(Cyclohexyl)-$CH$=$CH$-(Cyclohexyl) $\xrightarrow{KMnO_4/H^+}$ '$P$' (major product)
'$P$' is:

Write the main product of the given reactions:
$(1)$ $CH_3CH = CHCH_3 + HBr \to$
$(2)$ $CH_3-C(CH_3)=CH_2 + HBr \to$