Which of the following is not correct?

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Question

(D) $1$. Thermal stability decreases down the group as the bond dissociation energy decreases: $H_2O > H_2S > H_2Se > H_2Te > H_2Po$. This is correct.

Vedclass · Accepted Answer

Melting point : $H_2S < H_2Se < H_2Te < H_2O$

Vedclass · Answer

(D) $1$. Thermal stability decreases down the group as the bond dissociation energy decreases: $H_2O > H_2S > H_2Se > H_2Te > H_2Po$. This is correct.$2$. Reducing property increases down the group as the bond dissociation energy decreases: $H_2S $3$. Boiling point: $H_2O$ has the highest boiling point due to hydrogen bonding. For the rest,boiling point increases with increasing molecular mass: $H_2S $4$. Melting point: The trend for melting point is $H_2S < H_2Se < H_2O < H_2Te$. $H_2O$ does not have the highest melting point compared to $H_2Te$ because of the crystal structure differences. Thus,the statement in option $D$ is incorrect.

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