Which of the following is Mendius reduction?

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(D) The correct answer is $D$. Mendius reduction involves the reduction of nitriles $(R-CN)$ to primary amines $(R-CH_2NH_2)$ using reducing agents li

Vedclass · Accepted Answer

$R-CN \xrightarrow[	ext{or } LiAlH_4]{Na / CH_3OH} R-CH_2NH_2$

Vedclass · Answer

(D) The correct answer is $D$. Mendius reduction involves the reduction of nitriles $(R-CN)$ to primary amines $(R-CH_2NH_2)$ using reducing agents like sodium in ethanol or methanol ($Na / C_2H_5OH$ or $Na / CH_3OH$) or lithium aluminum hydride $(LiAlH_4)$. Explanation of other options: - $A$: This is Hofmann bromamide degradation,where an amide $(R-CONH_2)$ reacts with bromine and alkali to form a primary amine. - $B$: This is the $N$-alkylation of amines,where an amine reacts with excess alkyl halide to form a quaternary ammonium salt. - $C$: This is Hofmann elimination,where a quaternary ammonium hydroxide undergoes thermal decomposition to form an alkene and a tertiary amine.

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