Which of the following is the incorrect order | vedclass

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(C) $a)$ The $X-P-X$ bond angle follows the order $PBr_3 > PCl_3 > PF_3$ because as electronegativity decreases from $F$ to $Br$,the bond pair-bond pa

Vedclass · Accepted Answer

$PBr_4^+ > PCl_4^+ > PF_4^+$

Vedclass · Answer

(C) $a)$ The $X-P-X$ bond angle follows the order $PBr_3 > PCl_3 > PF_3$ because as electronegativity decreases from $F$ to $Br$,the bond pair-bond pair repulsion increases,leading to larger bond angles in $PBr_3$.$b)$ Similarly,for $OPX_3$ molecules,the bond angle follows the order $OPBr_3 > OPCl_3 > OPF_3$ due to the decreasing electronegativity of the halogen atoms.$c)$ All $PBr_4^+$,$PCl_4^+$,and $PF_4^+$ ions have a tetrahedral geometry with $sp^3$ hybridization and no lone pairs on the central $P$ atom,so their bond angles are all equal to $109.5^{\circ}$. Thus,the order $PBr_4^+ > PCl_4^+ > PF_4^+$ is incorrect.$d)$ $PCl_4^+$ has a tetrahedral geometry $(109.5^{\circ})$,whereas $PCl_3$ has a trigonal pyramidal geometry with a lone pair,which causes bond pair-bond pair repulsion to decrease,resulting in a bond angle less than $109.5^{\circ}$. Therefore,$PCl_4^+ > PCl_3$ is correct.

Which of the following is the incorrect order of $X-P-X$ bond angle?

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