Which of the following is incorrect about a p | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The correct answer is $D$. In a plane electromagnetic wave,the electric field $\vec{E}$ and the magnetic field $\vec{B}$ oscillate in the same pha

Vedclass · Accepted Answer

The electric field and magnetic field oscillate in opposite phase

Vedclass · Answer

(D) The correct answer is $D$. In a plane electromagnetic wave,the electric field $\vec{E}$ and the magnetic field $\vec{B}$ oscillate in the same phase. They are perpendicular to each other and also perpendicular to the direction of wave propagation. Since they oscillate in the same phase,the statement that they oscillate in opposite phase is incorrect. Additionally,the average energy density of the electric field is equal to the average energy density of the magnetic field,i.e.,$u_E = u_B = \frac{1}{4} \epsilon_0 E_0^2$.

Which of the following is incorrect about a plane electromagnetic wave?

Similar Questions

In an electromagnetic wave,if $\overrightarrow{E}$ is the electric field and $\overrightarrow{B}$ is the magnetic field,then the direction of propagation of the wave is given by:

In an electromagnetic wave,the electric field vector and magnetic field vector are given as $\vec{E} = E_{0} \hat{i}$ and $\vec{B} = B_{0} \hat{k}$ respectively. The direction of propagation of the electromagnetic wave is along:

If the magnetic field of a plane electromagnetic wave is given by (The speed of light $c = 3 \times 10^8 \, m/s$):
$B = 100 \times 10^{-6} \sin \left[ 2\pi \times 2 \times 10^{15} \left( t - \frac{x}{c} \right) \right]$
Then the maximum electric field associated with it is:

The electric field of a plane electromagnetic wave propagating along the $x$-direction in vacuum is $\overrightarrow{E} = E_{0} \hat{j} \cos(\omega t - kx)$. The magnetic field $\overrightarrow{B}$ at the moment $t = 0$ is:

$A$ point source of electromagnetic radiation has an average power output of $800 \, W$. The maximum value of the electric field at a distance $4.0 \, m$ from the source is .... $V/m$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module