Which of the following is correctly matched?

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(B) $1$. For $[Cu(NH_3)_4]^{2+}$,$Cu^{2+}$ is $3d^9$. It undergoes $dsp^2$ hybridization and is paramagnetic due to one unpaired electron.$2$. For $K_

Vedclass · Accepted Answer

$K_2[Ni(CN)_4]$: $dsp^2$,diamagnetic

Vedclass · Answer

(B) $1$. For $[Cu(NH_3)_4]^{2+}$,$Cu^{2+}$ is $3d^9$. It undergoes $dsp^2$ hybridization and is paramagnetic due to one unpaired electron.$2$. For $K_2[Ni(CN)_4]$,$Ni^{2+}$ is $3d^8$. $CN^-$ is a strong field ligand,causing pairing of electrons. It undergoes $dsp^2$ hybridization and is diamagnetic.$3$. $[Co(NH_3)_4(H_2O)_2]Cl_3$ involves $Co^{3+}$ $(3d^6)$. With weak field ligands,it undergoes $sp^3d^2$ hybridization and is paramagnetic.$4$. $[Pt(NH_3)_2Cl_2]$ is a square planar complex ($dsp^2$ hybridization) and is diamagnetic.Therefore,option $B$ is correctly matched.

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