Which of the following statements is correct?

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(D) For option $A$: The complex $[NiCl_4(NH_3)_2]^{2-}$ follows the formula $[Ma_4b_2]$,which exhibits geometrical isomerism (cis and trans forms).For

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$A$ and $C$ both

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(D) For option $A$: The complex $[NiCl_4(NH_3)_2]^{2-}$ follows the formula $[Ma_4b_2]$,which exhibits geometrical isomerism (cis and trans forms).For option $B$: $[Pt(NH_3)_2Cl_2]$ is a square planar complex $([Ma_2b_2])$ and exhibits cis-trans isomerism,not Fac-mer isomerism.For option $C$: $CoCl_3 \cdot 6H_2O$ can exist as $[Co(H_2O)_6]Cl_3$,$[Co(H_2O)_5Cl]Cl_2 \cdot H_2O$,and $[Co(H_2O)_4Cl_2]Cl \cdot 2H_2O$,thus exhibiting hydrate isomerism.Therefore,both $A$ and $C$ are correct.

Similar Questions

Number of stereoisomers possible for the octahedral complexes $[Co(NH_3)_3Cl_3]$ and $[Ni(en)_2Cl_2]$,respectively,are (where $en = 1,2-$ethylenediamine):

$A$ complex of the type $[M(AA)_{2}X_{2}]^{n+}$ is known to be optically active. What does this indicate about the structure of the complex? Give one example of such a complex.

The total number of geometrical isomers possible for an octahedral complex of the type $[MA_{2}B_{2}C_{2}]$ is ($M=$ transition metal; $A, B$ and $C$ are monodentate ligands).

Which of the following complexes is colored?

Assertion : $[Co(NO_2)_3(NH_3)_3]$ does not show optical isomerism.
Reason : It has a plane of symmetry.

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