Which of the following is an oxidizing agent?

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Question

(A) $Mn(CO)_5$ is an oxidizing agent because it has an odd number of electrons ($17$ valence electrons). It gains an electron to achieve the stable $1

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$Mn(CO)_5$

Vedclass · Answer

(A) $Mn(CO)_5$ is an oxidizing agent because it has an odd number of electrons ($17$ valence electrons). It gains an electron to achieve the stable $18$-electron configuration (Effective Atomic Number of $Kr = 36$). The reaction is: $Mn(CO)_5 + e^- \rightarrow [Mn(CO)_5]^-$. Since it accepts an electron,it acts as an oxidizing agent.

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