Which of the following is an oxidizing agent?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The $E.A.N.$ (Effective Atomic Number) of $Mn(CO)_5$ is $25 + 5 	imes 2 = 35$.Since $35$ is less than the atomic number of the next noble gas $(3

Vedclass · Accepted Answer

$Mn(CO)_5$

Vedclass · Answer

(A) The $E.A.N.$ (Effective Atomic Number) of $Mn(CO)_5$ is $25 + 5 	imes 2 = 35$.Since $35$ is less than the atomic number of the next noble gas $(36)$,it tends to gain one electron to achieve a stable $18$-electron configuration (or $36$ $E.A.N.$).Therefore,$Mn(CO)_5$ acts as an oxidizing agent by accepting an electron to form $[Mn(CO)_5]^-$,which has $36$ $E.A.N.$

Similar Questions

Which of the following is known as the $Christmas$ tree?

The existence of a substance in more than one solid modification is known as:

The catalyst used in the contact process is

Two solid spheres $A$ and $B$ made of the same material have radii $r_A$ and $r_B$ respectively. Both the spheres are cooled from the same temperature under the conditions valid for Newton's law of cooling. The ratio of the rate of change of temperature of $A$ and $B$ is :

The correct order of ionic radii of $Ce, La, Pm$ and $Yb$ in $+3$ oxidation state is

Vedclass Test Series

Exam Paper Generator

Online Exam Module