Which of the following is a low-spin complex?

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Question

(D) low-spin complex is formed when the crystal field splitting energy $(\Delta_o)$ is greater than the pairing energy $(P)$. This typically occurs wi

Vedclass · Accepted Answer

$[Fe(NH_3)_6]^{3+}$

Vedclass · Answer

(D) low-spin complex is formed when the crystal field splitting energy $(\Delta_o)$ is greater than the pairing energy $(P)$. This typically occurs with strong field ligands like $NH_3$ and $CN^-$. In $[Fe(NH_3)_6]^{3+}$,the central metal ion is $Fe^{3+}$ ($d^5$ configuration). $NH_3$ is a strong field ligand,which causes the electrons to pair up in the $t_{2g}$ orbitals,resulting in a low-spin configuration $(t_{2g}^5 e_g^0)$. In contrast,$[Ni(NH_3)_6]^{2+}$ $(d^8)$ and $[Cr(NH_3)_6]^{3+}$ $(d^3)$ do not exhibit low-spin/high-spin variations due to their specific electronic configurations. $[Ti(H_2O)_6]^{3+}$ $(d^1)$ also does not exhibit spin states. Therefore,$[Fe(NH_3)_6]^{3+}$ is the correct answer.

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