Which of the following is a correct statement | vedclass

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(A) . $Cu^{+} = [Ar] 3d^{10}$ (No unpaired electrons,so it is colourless). $Zn^{2+} = [Ar] 3d^{10}$ (No unpaired electrons,so it is colourless).$B$. $

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Aqueous solutions of $Cu^{+}$ and $Zn^{2+}$ are colourless

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(A) . $Cu^{+} = [Ar] 3d^{10}$ (No unpaired electrons,so it is colourless). $Zn^{2+} = [Ar] 3d^{10}$ (No unpaired electrons,so it is colourless).$B$. $Cu^{2+} = [Ar] 3d^9$ (One unpaired electron is present,so it is coloured). $Zn^{2+}$ is colourless.$C$. The colour of $Fe^{2+}$ is green while that of $Fe^{3+}$ is yellow/brown.$D$. $MnO_4^{-}$ contains no unpaired electrons,however,it is coloured due to charge transfer.Thus,only the statement given in option $A$ is correct.

Which of the following is a correct statement?

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