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(D) $I$. Pure $NaCl$ is not hygroscopic; it becomes hygroscopic only due to impurities like $CaCl_2$ and $MgCl_2$.$II$. Alkali metals have an electron

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$IV$ only

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(D) $I$. Pure $NaCl$ is not hygroscopic; it becomes hygroscopic only due to impurities like $CaCl_2$ and $MgCl_2$.$II$. Alkali metals have an electronic configuration of $ns^1$. The $(n-1)d$ subshell is not present for $Li$ $(n=2)$,and for others,it is completely filled,not vacant.$III$. $Na_2CO_3$ is a salt of a strong base $(NaOH)$ and a weak acid $(H_2CO_3)$,making it basic. $NaHCO_3$ is an amphiprotic species,and its solution is less basic than $Na_2CO_3$.$IV$. Alums are double salts with the general formula $M'M'''(SO_4)_2 \cdot 12H_2O$. $Li^{+}$ and $Mg^{2+}$ do not form alums because their ionic radii are too small to fit into the crystal lattice structure of alums.Therefore,only statement $IV$ is $CORRECT$.

Which of the following is $CORRECT$ regarding alkali metals?
$I$. Pure $NaCl$ is hygroscopic
$II$. $(n - 1)d$ subshell is vacant only
$III$. Aqueous $NaHCO_3$ solution is more basic than $Na_2CO_3$ solution
$IV$. Both $Li^{+}$ and $Mg^{2+}$ do not form alums

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Which of the following is $CORRECT$ regarding alkali metals?$I$. Pure $NaCl$ is hygroscopic$II$. $(n - 1)d$ subshell is vacant only$III$. Aqueous $NaHCO_3$ solution is more basic than $Na_2CO_3$ solution$IV$. Both $Li^{+}$ and $Mg^{2+}$ do not form alums