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(D) To find the number of atoms,we calculate the moles of molecules and multiply by the atomicity of the substance.$A) \ 12 \ g \ He: 	ext{moles} = \

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$2.45 \ g \ H_2SO_4$

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(D) To find the number of atoms,we calculate the moles of molecules and multiply by the atomicity of the substance.$A) \ 12 \ g \ He: 	ext{moles} = \frac{12}{4} = 3 \ mol 	ext{ atoms}$.$B) \ 1.8 \ g \ H_2O: 	ext{moles} = \frac{1.8}{18} = 0.1 \ mol 	ext{ molecules}$. $	ext{Atoms} = 0.1 	imes 3 = 0.3 \ mol 	ext{ atoms}$.$C) \ 22 \ g \ CO_2: 	ext{moles} = \frac{22}{44} = 0.5 \ mol 	ext{ molecules}$. $	ext{Atoms} = 0.5 	imes 3 = 1.5 \ mol 	ext{ atoms}$.$D) \ 2.45 \ g \ H_2SO_4: 	ext{moles} = \frac{2.45}{98} = 0.025 \ mol 	ext{ molecules}$. $	ext{Atoms} = 0.025 	imes 7 = 0.175 \ mol 	ext{ atoms}$.Comparing the values: $3 > 1.5 > 0.3 > 0.175$. Thus,$2.45 \ g \ H_2SO_4$ has the minimum number of atoms.

Which of the following has the minimum number of atoms?

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