Which of the following gives an alcohol and salt of carboxylic acid when reacted with conc. $NaOH$?

The product $(A)$ of the reaction is:

The compound $A$,$C_{8}H_{8}O_{2}$,reacts with acetophenone to form a single product via cross-Aldol condensation. The compound $A$ on reaction with conc. $NaOH$ forms a substituted benzyl alcohol. Identify compound $A$.

Predict the product of the following reaction:
$p-CH_3-C_6H_4-CHO + p-CH_3-C_6H_4-CO-CH_3 \xrightarrow{\bar{O}H, \Delta} \text{Product}$

Metaformaldehyde is:

Match the reactions in Column $I$ with appropriate options in Column $II$.

Column $I$	Column $II$
$A$. $Ph-N_2Cl + Ph-OH \xrightarrow{NaOH/H_2O, 0^{\circ}C} Ph-N=N-Ph-OH$	$p$. Racemic mixture
$B$. $Pinacol \xrightarrow{H_2SO_4} Pinacolone$	$q$. Addition reaction
$C$. $Ph-CO-CH_3 \xrightarrow{1. LiAlH_4, 2. H_3O^+} Ph-CH(OH)-CH_3$	$r$. Substitution reaction
$D$. $4-chlorocyclohexanethiol \xrightarrow{Base} Thiacycloheptane$	$s$. Coupling reaction
	$t$. Carbocation intermediate