Which of the following exhibit ionization iso | vedclass

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(A) Ionization isomerism occurs when the counter ion in a coordination complex is a potential ligand and can displace a ligand from the coordination s

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$II$ & $III$ only

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(A) Ionization isomerism occurs when the counter ion in a coordination complex is a potential ligand and can displace a ligand from the coordination sphere.$I) [Cr(NH_3)_4Cl_2]Cl$ can form $[Cr(NH_3)_4Cl_3]$ (No,$Cl$ is already inside).$II) [Ti(H_2O)_5Cl](NO_3)_2$ can form $[Ti(H_2O)_5(NO_3)]Cl(NO_3)$ or $[Ti(H_2O)_5(NO_3)_2]Cl$. This exhibits ionization isomerism.$III) [Pt(en)(NH_3)Cl]NO_3$ can form $[Pt(en)(NH_3)(NO_3)]Cl$. This exhibits ionization isomerism.$IV) [Co(NH_3)_4(NO_3)_2]NO_3$ can form $[Co(NH_3)_4(NO_3)_3]$. This exhibits ionization isomerism.However,looking at the options provided,the most appropriate pair exhibiting this behavior clearly is $II$ and $III$.

Column-$I$	Column-$II$
$(a) [Pt(NH_3)_3Cl]Br$	$(P) \text{Coordination isomerism}$
$(b) [Cr(NH_3)_5(NCS)]^{+2}$	$(Q) \text{Ionisation isomerism}$
$(c) [Co(H_2O)_6]Cl_3$	$(R) \text{Linkage isomerism}$
$(d) [PtCl_4][Pt(NH_3)_4]$	$(S) \text{Hydrate isomerism}$

Which of the following exhibit ionization isomerism?
$I) [Cr(NH_3)_4Cl_2]Cl$
$II) [Ti(H_2O)_5Cl](NO_3)_2$
$III) [Pt(en)(NH_3)Cl]NO_3$
$IV) [Co(NH_3)_4(NO_3)_2]NO_3$

Similar Questions

Assertion : $[Co(NO_2)_3(NH_3)_3]$ does not show optical isomerism.
Reason : It has a plane of symmetry.

In $[Cr(C_2O_4)_3]^{3-}$,the isomerism shown is :-

Match the column:
Column-$I$ Column-$II$
$(a) [Pt(NH_3)_3Cl]Br$ $(P) \text{Coordination isomerism}$
$(b) [Cr(NH_3)_5(NCS)]^{+2}$ $(Q) \text{Ionisation isomerism}$
$(c) [Co(H_2O)_6]Cl_3$ $(R) \text{Linkage isomerism}$
$(d) [PtCl_4][Pt(NH_3)_4]$ $(S) \text{Hydrate isomerism}$

The species with spin only magnetic moment of $\sqrt{24} \, BM$ is

Which of the following compounds exhibits linkage isomerism?

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Which of the following exhibit ionization isomerism?$I) [Cr(NH_3)_4Cl_2]Cl$$II) [Ti(H_2O)_5Cl](NO_3)_2$$III) [Pt(en)(NH_3)Cl]NO_3$$IV) [Co(NH_3)_4(NO_3)_2]NO_3$