Which of the following equations is correct r | vedclass

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(D) The transport of oxygen involves the reversible binding of oxygen with haemoglobin $(Hb)$ to form oxyhaemoglobin $(HbO_{2})$.In the lungs,the high

Vedclass · Accepted Answer

$HbO_{2} \underset{	ext{Association in lungs}}{\stackrel{	ext{Dissociation in tissues}}{ightleftharpoons}} Hb + O_{2}$

Vedclass · Answer

(D) The transport of oxygen involves the reversible binding of oxygen with haemoglobin $(Hb)$ to form oxyhaemoglobin $(HbO_{2})$.In the lungs,the high partial pressure of oxygen $(pO_{2})$ and low partial pressure of carbon dioxide $(pCO_{2})$ favor the association of oxygen with haemoglobin: $Hb + O_{2} \rightarrow HbO_{2}$.In the tissues,the low partial pressure of oxygen $(pO_{2})$ and high partial pressure of carbon dioxide $(pCO_{2})$ favor the dissociation of oxyhaemoglobin to release oxygen: $HbO_{2} \rightarrow Hb + O_{2}$.Therefore,the correct reversible equation is $Hb + O_{2} \rightleftharpoons HbO_{2}$,where association occurs in the lungs and dissociation occurs in the tissues. Option $D$ correctly represents this process.

Which of the following equations is correct regarding the transport of oxygen?

Similar Questions

Identify the given curve.

$100 \ ml$ of oxygenated blood contains:

Approximately how many $mL$ of $CO_2$ is delivered to the alveoli by every $100$ $mL$ of deoxygenated blood?

$A$: Human blood always contains a higher amount of $CO_2$ than $O_2$.
$R$: The solubility coefficient of $CO_2$ is higher than that of $O_2$.

Describe: Transport of $CO_{2}$.

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