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(D) The standard enthalpy of formation is defined as the enthalpy change when $1 \ mol$ of a compound is formed from its constituent elements in their

Vedclass · Accepted Answer

$C(graphite) + 2H_{2(g)} + \frac{1}{2}O_{2(g)} 	o CH_3OH_{(l)}$

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(D) The standard enthalpy of formation is defined as the enthalpy change when $1 \ mol$ of a compound is formed from its constituent elements in their most stable standard states at a given temperature (usually $298 \ K$).$1$. Carbon must be in its most stable form,which is $C(graphite)$.$2$. Hydrogen must be in its standard state,$H_{2(g)}$.$3$. Oxygen must be in its standard state,$O_{2(g)}$.$4$. The product must be $1 \ mol$ of the compound,$CH_3OH_{(l)}$.Therefore,the correct equation is $C(graphite) + 2H_{2(g)} + \frac{1}{2}O_{2(g)} 	o CH_3OH_{(l)}$.

Which of the following equations corresponds to the definition of enthalpy of formation at $298 \ K$?

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