Which of the following electronic configurati | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The $I.P.$ (Ionization Potential) depends on the stability of the electronic configuration and the shielding effect.Comparing the given configurat

Vedclass · Accepted Answer

$1s^2 2s^2 2p^6 3s^2 3p^1$

Vedclass · Answer

(D) The $I.P.$ (Ionization Potential) depends on the stability of the electronic configuration and the shielding effect.Comparing the given configurations:$A$: $3p^6$ (Noble gas,very stable,high $I.P.$)$B$: $3p^5$ (High $I.P.$ due to high effective nuclear charge)$C$: $3s^2$ (Fully filled $s$-orbital,stable,high $I.P.$)$D$: $3s^2 3p^1$ (The electron is being removed from the $3p$ orbital,which is shielded by the $3s^2$ electrons and is further from the nucleus compared to the $3s$ orbital).Therefore,the configuration $1s^2 2s^2 2p^6 3s^2 3p^1$ has the least $I.P.$ value.

Which of the following electronic configurations will have the least $I.P.$ value?

Similar Questions

Which of the following gaseous atoms has the highest value of $IE$?

Identify the element which has the highest second ionisation enthalpy.

The correct order of ionisation energy for comparing carbon,nitrogen,and oxygen atoms is:

How would you explain the fact that the first ionization enthalpy of sodium is lower than that of magnesium but its second ionization enthalpy is higher than that of magnesium?

The correct order of $C$,$N$,$O$ and $F$ in terms of second ionisation potential is

Vedclass Test Series

Exam Paper Generator

Online Exam Module