Which of the following electronic configurati | vedclass

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(A) Spin multiplicity is calculated using the formula $2S + 1$,where $S$ is the total spin of the electrons in the valence shell.For $2p^3$,there are

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$1s^2, 2s^2, 2p^3$

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(A) Spin multiplicity is calculated using the formula $2S + 1$,where $S$ is the total spin of the electrons in the valence shell.For $2p^3$,there are $3$ unpaired electrons,so $S = 3 	imes (1/2) = 3/2$. Multiplicity $= 2(3/2) + 1 = 4$.For $2p^4$,there are $2$ unpaired electrons,so $S = 2 	imes (1/2) = 1$. Multiplicity $= 2(1) + 1 = 3$.For $2p^5$,there is $1$ unpaired electron,so $S = 1/2$. Multiplicity $= 2(1/2) + 1 = 2$.For $2p^6$,there are $0$ unpaired electrons,so $S = 0$. Multiplicity $= 2(0) + 1 = 1$.Thus,the configuration $1s^2, 2s^2, 2p^3$ has the maximum spin multiplicity.

Which of the following electronic configurations has the maximum total spin multiplicity?

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