Which of the following does not have an asymm | vedclass

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(C) An asymmetric carbon (chiral center) is a carbon atom bonded to four different groups.$A$. In $1$-chloro-$2$-bromocyclopropane,the carbons at posi

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$C_2H_2ClBr$

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(C) An asymmetric carbon (chiral center) is a carbon atom bonded to four different groups.$A$. In $1$-chloro-$2$-bromocyclopropane,the carbons at positions $1$ and $2$ are bonded to four different groups (e.g.,$C_1$ is bonded to $H$,$Cl$,$C_2$,and $C_3$),so it has asymmetric carbons.$B$. In $2$-methylazetidine,the carbon at position $2$ is bonded to $H$,$CH_3$,$N$,and $C_3$,making it an asymmetric carbon.$C$. In $C_2H_2ClBr$ (which is $CH_2Cl-CH_2Br$ or $CHCl=CHBr$),there is no carbon atom bonded to four different groups. For example,in $1$-bromo-$2$-chloroethane $(CH_2Cl-CH_2Br)$,each carbon is bonded to two $H$ atoms,which are identical.$D$. In $3$-chlorobutane $(CH_3-CH_2-CHCl-CH_3)$,the carbon at position $3$ is bonded to $H$,$Cl$,$CH_3$,and $CH_2CH_3$,which are four different groups,so it is an asymmetric carbon.Therefore,the molecule that does not have an asymmetric carbon is $C_2H_2ClBr$.

Which of the following does not have an asymmetric carbon?

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