Which of the following diagrams shows the cor | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The polarity of a bond is directly proportional to the difference in electronegativity $(\Delta EN)$ between the bonded atoms.Electronegativity va

Vedclass · Accepted Answer

Vedclass · Answer

(D) The polarity of a bond is directly proportional to the difference in electronegativity $(\Delta EN)$ between the bonded atoms.Electronegativity values are: $F = 4.0$,$O = 3.5$,$Cl = 3.0$,$S = 2.5$,$H = 2.1$.Calculating $\Delta EN$ for each bond:$F-H: 4.0 - 2.1 = 1.9$$O-H: 3.5 - 2.1 = 1.4$$Cl-H: 3.0 - 2.1 = 0.9$$S-H: 2.5 - 2.1 = 0.4$Comparing the polarities: $F-H > O-H > Cl-H > S-H$.Looking at the cycle in the diagrams:$O-H (1.4) \rightarrow Cl-H (0.9)$ (Decrease)$Cl-H (0.9) \rightarrow F-H (1.9)$ (Increase)$F-H (1.9) \rightarrow S-H (0.4)$ (Decrease)$S-H (0.4) \rightarrow O-H (1.4)$ (Increase)This sequence matches Diagram $D$.

Which of the following diagrams shows the correct change in the polarity of the bond?

Similar Questions

Among the following molecules,the highest dipole moment is

Which of the following compounds will show the highest dipole moment?

Which of the following substances has the lowest dipole moment?

Explain why $BeH_{2}$ molecule has a zero dipole moment although the $Be-H$ bonds are polar.

The molecular size of $ICl$ and $Br_2$ is approximately the same,but the $b.p.$ of $ICl$ is about $40 \ ^oC$ higher than that of $Br_2$. This is because:

Vedclass Test Series

Exam Paper Generator

Online Exam Module