Which of the following diagrams or statements | vedclass

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(D) For $sp$ hybridization: The mixing of one $s$ and one $p$ orbital (e.g.,$p_y$) results in two $sp$ hybrid orbitals oriented along the axis of the

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All of these

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(D) For $sp$ hybridization: The mixing of one $s$ and one $p$ orbital (e.g.,$p_y$) results in two $sp$ hybrid orbitals oriented along the axis of the $p$ orbital used. Thus,$s + p_y 	o 2sp$ along the $y$-axis is correct.For $sp^2$ hybridization: The mixing of one $s$ and two $p$ orbitals (e.g.,$p_y$ and $p_z$) results in three $sp^2$ hybrid orbitals lying in the plane defined by those two $p$ orbitals (the $yz$ plane). Thus,$s + p_y + p_z 	o sp^2$ orbitals in the $yz$ plane is correct.For $sp^3d^2$ hybridization: The mixing of one $s$,three $p$,and two $d$ orbitals results in six $sp^3d^2$ hybrid orbitals,which are directed towards the corners of an octahedron. Thus,this statement is also correct.Since all statements are correct,the correct option is $D$.

Element	Electronegativity Value
$W$	$2.7$
$X$	$2.1$
$Y$	$0.8$
$Z$	$3.4$

Which of the following diagrams or statements is correct for the hybrid orbitals?

Similar Questions

Element Electronegativity Value
$W$ $2.7$
$X$ $2.1$
$Y$ $0.8$
$Z$ $3.4$
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