Which of the following contains the maximum n | vedclass

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(C) The number of molecules is calculated using the formula: $	ext{Number of molecules} = \frac{	ext{mass of substance}}{	ext{molar mass}} 	imes N

Vedclass · Accepted Answer

$1\,g$ $H_2$

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(C) The number of molecules is calculated using the formula: $	ext{Number of molecules} = \frac{	ext{mass of substance}}{	ext{molar mass}} 	imes N_A$.For $1\,g$ of $H_2$: $	ext{Molar mass} = 2\,g/mol$. $	ext{Number of molecules} = \frac{1}{2} 	imes N_A = 0.5 N_A$.For $1\,g$ of $CO_2$: $	ext{Molar mass} = 44\,g/mol$. $	ext{Number of molecules} = \frac{1}{44} 	imes N_A \approx 0.0227 N_A$.For $1\,g$ of $N_2$: $	ext{Molar mass} = 28\,g/mol$. $	ext{Number of molecules} = \frac{1}{28} 	imes N_A \approx 0.0357 N_A$.For $1\,g$ of $CH_4$: $	ext{Molar mass} = 16\,g/mol$. $	ext{Number of molecules} = \frac{1}{16} 	imes N_A = 0.0625 N_A$.Comparing the values,$0.5 N_A$ is the largest. Therefore,$1\,g$ of $H_2$ contains the maximum number of molecules.

Which of the following contains the maximum number of molecules?

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