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(D) To find the number of atoms,we calculate the moles of molecules and multiply by the atomicity and Avogadro's number $(N_A)$:$A$. $2 	ext{ g}$ of

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$A, C$ and $E$ only

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(D) To find the number of atoms,we calculate the moles of molecules and multiply by the atomicity and Avogadro's number $(N_A)$:$A$. $2 	ext{ g}$ of $O_2 = 2/32 = 0.0625 	ext{ mol}$. Atoms = $0.0625 	imes 2 	imes N_A = 0.125 N_A$.$B$. $4 	ext{ g}$ of $SO_2 = 4/64 = 0.0625 	ext{ mol}$. Atoms = $0.0625 	imes 3 	imes N_A = 0.1875 N_A$.$C$. $1400 	ext{ mL}$ of $O_2 = 1.4 	ext{ L} / 22.4 	ext{ L/mol} = 0.0625 	ext{ mol}$. Atoms = $0.0625 	imes 2 	imes N_A = 0.125 N_A$.$D$. $0.05 	ext{ L}$ of $He = 0.05 / 22.4 \approx 0.00223 	ext{ mol}$. Atoms = $0.00223 N_A$.$E$. $0.0625 	ext{ mol}$ of $H_2$. Atoms = $0.0625 	imes 2 	imes N_A = 0.125 N_A$.Comparing the results,options $A, C$,and $E$ have the same number of atoms $(0.125 N_A)$.

Which of the following contain the same number of atoms?
$A$. $2 \text{ g}$ of $O_2$ gas
$B$. $4 \text{ g}$ of $SO_2$ gas
$C$. $1400 \text{ mL}$ of $O_2$ at $STP$
$D$. $0.05 \text{ L}$ of $He$ at $STP$
$E$. $0.0625 \text{ mol}$ of $H_2$ gas
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Which of the following contain the same number of atoms?$A$. $2 \text{ g}$ of $O_2$ gas$B$. $4 \text{ g}$ of $SO_2$ gas$C$. $1400 \text{ mL}$ of $O_2$ at $STP$$D$. $0.05 \text{ L}$ of $He$ at $STP$$E$. $0.0625 \text{ mol}$ of $H_2$ gasChoose the correct answer from the options given below: