Which of the following compounds will not und | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Friedel-Crafts reaction requires the formation of a stable carbocation or an acylium ion intermediate. In the case of vinyl chloride $(CH_2=CH-Cl)

Vedclass · Accepted Answer

$CH_2=CH-Cl$ (Vinyl chloride)

Vedclass · Answer

(B) Friedel-Crafts reaction requires the formation of a stable carbocation or an acylium ion intermediate. In the case of vinyl chloride $(CH_2=CH-Cl)$,the chlorine atom is directly attached to an $sp^2$ hybridized carbon atom. The lone pair of electrons on the chlorine atom participates in resonance with the double bond,giving the $C-Cl$ bond partial double bond character. This makes the cleavage of the $C-Cl$ bond very difficult,and the resulting vinyl carbocation $(CH_2=CH^+)$ is highly unstable due to the $sp$ hybridization of the positively charged carbon. Therefore,vinyl chloride does not undergo Friedel-Crafts reaction.

Which of the following compounds will not undergo Friedel-Crafts reaction with benzene?

Similar Questions

Which sequence of reagents is useful for the conversion of $C_6H_5CH_2CH_3$ to $C_6H_5CH=CH_2$?

Write a note on $S_{N}2$ mechanism.

Chloroform is slowly oxidized by air in the presence of light to form:

Which of the following has the shortest $C-Cl$ bond?

Which compound undergoes nucleophilic substitution with $NaCN$ at the fastest rate?

Vedclass Test Series

Exam Paper Generator

Online Exam Module