Which of the following compounds is more acid | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The acidity of alcohols depends on the stability of the alkoxide ion formed after the loss of a proton $(H^+)$. Alkyl groups are electron-donating

Vedclass · Accepted Answer

$CH_3-OH$

Vedclass · Answer

(D) The acidity of alcohols depends on the stability of the alkoxide ion formed after the loss of a proton $(H^+)$. Alkyl groups are electron-donating groups ($+I$ effect). As the number of alkyl groups attached to the carbon atom bearing the $-OH$ group increases,the electron density on the oxygen atom increases due to the $+I$ effect,which destabilizes the alkoxide ion. Therefore,the order of acidity is: $primary > secondary > tertiary$. Among the given options: $(A)$ $(CH_3)_3C-OH$ is a tertiary alcohol. $(B)$ $CH_3-CH_2-CH_2-OH$ is a primary alcohol. $(C)$ $CH_3-CH(OH)-CH_3$ is a secondary alcohol. $(D)$ $CH_3-OH$ is methanol (the simplest alcohol with no alkyl group attached to the carbon bearing $-OH$). Since methanol has no electron-donating alkyl groups to destabilize the methoxide ion,it is the most acidic among the given options.

Which of the following compounds is more acidic?

Similar Questions

How many primary alcohol isomers are possible for the molecular formula ${C_5}{H_{11}}OH$?

The correct order of the solubility of the different alcohols in water is

In esterification,the reactivity of alcohols is:

Treatment of a $2^{\circ} \text{ alcohol}$ with $CrO_3/H_2SO_4$ yields a/an

Identify the reagents $X, Y, Z$ for the following dehydration reactions of alcohols:
$CH_3-CH_2-OH \xrightarrow{X} CH_2=CH_2 + H_2O$
$CH_3-CH(OH)-CH_3 \xrightarrow{Y} CH_3-CH=CH_2 + H_2O$
$(CH_3)_3C-OH \xrightarrow{Z} (CH_3)_2C=CH_2 + H_2O$

Vedclass Test Series

Exam Paper Generator

Online Exam Module