Which of the following compounds has a Van't | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The Van't Hoff factor $i$ represents the number of particles a solute dissociates into in a solution. For $K_2SO_4$,$i = 3$ $(2K^+ + SO_4^{2-})$.

Vedclass · Accepted Answer

$MgSO_4$

Vedclass · Answer

(D) The Van't Hoff factor $i$ represents the number of particles a solute dissociates into in a solution. For $K_2SO_4$,$i = 3$ $(2K^+ + SO_4^{2-})$. For $NaHSO_4$,$i = 2$ ($Na^+ + H^+ + SO_4^{2-}$ is incorrect,it dissociates as $Na^+ + HSO_4^-$ in dilute solution,so $i = 2$). For Sugar,$i = 1$ (non-electrolyte). For $MgSO_4$,$i = 2$ $(Mg^{2+} + SO_4^{2-})$. Both $NaHSO_4$ and $MgSO_4$ have $i = 2$. However,$MgSO_4$ is the standard example for a $1:1$ electrolyte dissociating into $2$ ions.

Which of the following compounds has a Van't Hoff factor $i$ equal to $2$ for a dilute solution?

Similar Questions

Write the value of the van't Hoff factor $(i)$ for $K_{2}SO_{4}$ and $K_{4}[Fe(CN)_{6}]$.

The freezing point of a $0.2 \ m$ aqueous solution of a weak acid $(HX)$ which is $20\%$ ionized is ......... $^oC$. (Given: $K_f = 1.86 \ ^oC/m$ for water)

$0.5$ molal aqueous solution of a weak acid $(HX)$ is $20\%$ ionised. If $K_f$ for water is $1.86\, K\, kg\, mol^{-1}$,the lowering in freezing point of the solution is $........ K$.

Explain the van't Hoff factor and provide its formula.

Which of the following aqueous solutions should have the highest boiling point?

Vedclass Test Series

Exam Paper Generator

Online Exam Module