Which of the following compounds are partiall | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $Fe(OH)_3$ and $Al(OH)_3$ are insoluble in $NH_4OH$ solution because $NH_4OH$ is a weak base and cannot provide enough $OH^-$ ions to dissolve the

Vedclass · Accepted Answer

$I, III$ and $IV$

Vedclass · Answer

(C) $Fe(OH)_3$ and $Al(OH)_3$ are insoluble in $NH_4OH$ solution because $NH_4OH$ is a weak base and cannot provide enough $OH^-$ ions to dissolve these amphoteric or basic hydroxides.$Ag_2CrO_4$ (silver chromate) is insoluble in $NH_4OH$.$Ag_2CO_3$ (silver carbonate) is soluble in $NH_4OH$ due to the formation of the complex $[Ag(NH_3)_2]^+$.Therefore,$Fe(OH)_3$,$Ag_2CrO_4$,and $Al(OH)_3$ are insoluble or partially soluble in $NH_4OH$ solution.Thus,the correct option is $C$.

Which of the following compounds are partially soluble or insoluble in $NH_4OH$ solution?
$(I)$ $Fe(OH)_3$
$(II)$ $Ag_2CrO_4$
$(III)$ $Al(OH)_3$
$(IV)$ $Ag_2CO_3$

Similar Questions

For a concentrated solution of a weak electrolyte ($K_{eq} = $ equilibrium constant) $A_2B_3$ of concentration '$c$',the degree of dissociation '$\alpha$' is

$Fe(OH)_3$ can be separated from $Al(OH)_3$ by addition of

Which $pH$ value is higher in the following pairs?
$(a)$ $0.1 \ M \ HCl$ and $0.1 \ M \ NaOH$
$(b)$ $0.1 \ M \ HCl$ and $0.01 \ M \ HCl$
$(c)$ $0.1 \ M \ NaOH$ and $0.01 \ M \ NaOH$

Which of the following undergoes hydrolysis when dissolved in water?

The ionization constant of dimethylamine is $5.4 \times 10^{-4}$. Calculate its degree of ionization in its $0.02 \ M$ solution. What percentage of dimethylamine is ionized if the solution is also $0.1 \ M$ in $NaOH$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Which of the following compounds are partially soluble or insoluble in $NH_4OH$ solution?$(I)$ $Fe(OH)_3$$(II)$ $Ag_2CrO_4$$(III)$ $Al(OH)_3$$(IV)$ $Ag_2CO_3$