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(B) The reaction with hot $KMnO_4/H^+$ is an oxidative cleavage reaction,similar to oxidative ozonolysis.It cleaves double bonds to form carboxylic ac

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$3-$vinylcyclohex$-1-$ene

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(B) The reaction with hot $KMnO_4/H^+$ is an oxidative cleavage reaction,similar to oxidative ozonolysis.It cleaves double bonds to form carboxylic acids or ketones,and terminal double bonds are oxidized to $CO_2$ and $H_2O$.The product shown is a substituted pentanedioic acid derivative with a $CO_2$ byproduct.Analyzing the structure of the product,it corresponds to the oxidative cleavage of $3$-vinylcyclohex-$1$-ene (Option $B$).The double bond in the ring at position $1$ and the vinyl group at position $3$ are cleaved to yield the observed dicarboxylic acid and $CO_2$.

Which of the following compounds was the starting material for the oxidation shown below?

Similar Questions

Among the following pairs,in which case does the second compound have a higher heat of hydrogenation?

Consider the following reaction in which the intermediate carbocation loses $H^{+}$ to give the final product:
Which of the following energy profiles best represents the overall reaction?

What is the major product expected from the following reaction?

In the hydrocarbon,$CH_3(1) - CH(2) = CH(3) - CH_2(4) - C(5) \equiv CH(6)$,the state of hybridization of carbons $1, 3$ and $5$ are in the following sequence:

$CH_3-C(CH_3)=CH_2 + (CH_3)_3CH \xrightarrow[273 \ K]{HF} C_8H_{18} (A)$
Unknown $(A)$ in the above reaction is:

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