Which of the following compounds shows geomet | vedclass

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(C) For a compound to show geometrical isomerism,the carbon atoms involved in the double bond must be attached to two different groups.$(A)$ $2-$methy

Vedclass · Accepted Answer

$4-$methylpent$-2-$ene

Vedclass · Answer

(C) For a compound to show geometrical isomerism,the carbon atoms involved in the double bond must be attached to two different groups.$(A)$ $2-$methylpent$-2-$ene: $(CH_3)_2C=CH-CH_2-CH_3$. The carbon at position $2$ is attached to two identical methyl groups,so it does not show geometrical isomerism.$(B)$ $4-$methylpent$-1-$ene: $CH_2=CH-CH_2-CH(CH_3)_2$. The terminal carbon $(C_1)$ is attached to two identical hydrogen atoms,so it does not show geometrical isomerism.$(C)$ $4-$methylpent$-2-$ene: $CH_3-CH=CH-CH_2-CH(CH_3)_2$. The carbons at positions $2$ and $3$ are each attached to two different groups ($-H$ and $-CH_3$ on $C_2$; $-H$ and $-CH_2CH(CH_3)_2$ on $C_3$). Thus,it shows geometrical isomerism.$(D)$ $2-$methylpent$-1-$ene: $CH_2=C(CH_3)-CH_2-CH_2-CH_3$. The terminal carbon $(C_1)$ is attached to two identical hydrogen atoms,so it does not show geometrical isomerism.

Which of the following compounds shows geometrical isomerism?

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