Which of the following compounds is diamagnet | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $K_4[Fe(CN)_5(O_2)]$ contains the superoxide ion $O_2^-$,which has an unpaired electron,making it paramagnetic. In $[NiF_6]^{2-}$,$Ni$ is in the $

Vedclass · Accepted Answer

None of these

Vedclass · Answer

(D) $K_4[Fe(CN)_5(O_2)]$ contains the superoxide ion $O_2^-$,which has an unpaired electron,making it paramagnetic. In $[NiF_6]^{2-}$,$Ni$ is in the $+4$ oxidation state ($d^6$ configuration). With $F^-$ as a weak field ligand,the electrons remain unpaired,making it paramagnetic. In $[Fe(H_2O)_5(NO)]^{2+}$,$Fe$ is in the $+1$ oxidation state $(d^7)$ and $NO$ is $NO^+$. This complex is known to be paramagnetic due to the presence of unpaired electrons. Therefore,none of the given complexes are diamagnetic.

Which of the following compounds is diamagnetic?

Similar Questions

How many pairs of enantiomers are possible for the following complex compound,$[M(AB)(CD)ef]^{n \pm}$ (where $AB, CD$ are unsymmetrical bidentate ligands,and $e, f$ are monodentate ligands)?

The correct statement about the magnetic properties of $[Fe(CN)_6]^{3-}$ and $[FeF_6]^{3-}$ is

$[Co(NH_3)_4Cl_2]^+$ exhibits

The tetrahedral $[CoI_4]^{2-}$ and square planar $[PdBr_4]^{2-}$ complex ions are respectively:

The correct order of the increasing magnetic moments for the following ions is $NiCl_4^{2-}$,$Fe(H_2O)_6^{2+}$,$Ni(CN)_4^{2-}$,and $Cu(H_2O)_6^{2+}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module