Which of the following complexes will absorb | vedclass

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(C) The wavelength of light absorbed $(\lambda)$ is inversely proportional to the crystal field splitting energy $(\Delta_o)$.
$\lambda \propto \frac

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$[CoCl(NH_3)_5]^{2+}$

Vedclass · Answer

(C) The wavelength of light absorbed $(\lambda)$ is inversely proportional to the crystal field splitting energy $(\Delta_o)$.
$\lambda \propto \frac{1}{\Delta_o}$.
To absorb the maximum wavelength,the complex must have the minimum crystal field splitting energy $(\Delta_o)$.
According to the spectrochemical series,the strength of ligands is: $CN^{-} > NH_3 > H_2O > Cl^{-}$.
Among the given ligands,$Cl^{-}$ is the weakest ligand,which results in the smallest $\Delta_o$ value.
Therefore,the complex $[CoCl(NH_3)_5]^{2+}$ will have the minimum $\Delta_o$ and will absorb the maximum wavelength of light.

List-$I$ (Complex)	List-$II$ ($CFSE$ in $\Delta_0$)
$A$. $[Ti(H_2O)_6]^{2+}$	$I$. $-1.2$
$B$. $[V(H_2O)_6]^{2+}$	$II$. $-0.8$
$C$. $[Mn(H_2O)_6]^{3+}$	$III$. $-0.6$
$D$. $[Fe(H_2O)_6]^{3+}$	$IV$. $0$

Which of the following complexes will absorb the maximum wavelength of light?

Similar Questions

Explain crystal field splitting in tetrahedral complexes.

Match List-$I$ with List-$II$:

List-$I$ (Complex) List-$II$ ($CFSE$ in $\Delta_0$)

$A$. $[Ti(H_2O)_6]^{2+}$ $I$. $-1.2$

$B$. $[V(H_2O)_6]^{2+}$ $II$. $-0.8$

$C$. $[Mn(H_2O)_6]^{3+}$ $III$. $-0.6$

$D$. $[Fe(H_2O)_6]^{3+}$ $IV$. $0$

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