Which of the following complexes is paramagne | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To determine the magnetic nature,we calculate the number of unpaired electrons in each complex:$1$. In $[Co(NH_3)_6]^{3+}$,$Co^{3+}$ is $d^6$. $NH

Vedclass · Accepted Answer

$[NiCl_4]^{2-}$

Vedclass · Answer

(D) To determine the magnetic nature,we calculate the number of unpaired electrons in each complex:$1$. In $[Co(NH_3)_6]^{3+}$,$Co^{3+}$ is $d^6$. $NH_3$ is a strong field ligand,causing pairing. All electrons are paired,so it is diamagnetic.$2$. In $[Ni(CO)_4]$,$Ni$ is $d^8 s^2$. $CO$ is a strong field ligand,causing $4s$ electrons to pair into $3d$. All electrons are paired,so it is diamagnetic.$3$. In $[Ni(CN)_4]^{2-}$,$Ni^{2+}$ is $d^8$. $CN^-$ is a strong field ligand,causing pairing in $3d$ orbitals. All electrons are paired,so it is diamagnetic.$4$. In $[NiCl_4]^{2-}$,$Ni^{2+}$ is $d^8$. $Cl^-$ is a weak field ligand,so no pairing occurs. There are $2$ unpaired electrons in the $3d$ orbitals,making it paramagnetic.

Which of the following complexes is paramagnetic?

Similar Questions

Which of the following ions is paramagnetic?

Which type of isomerism is exhibited by the square planar complex shown in the image?

Identify the number of complexes that are optically active:
$[Co(en)_3]^{3+}$; $[Co(NH_3)_4Cl_2]^{+}$; $[CoCl_2(en)_2]^{+}$; $[Co(NH_3)_3(NO_2)_3]$

Which complex is likely to show optical activity?

Which of the following represents a pair of enantiomers?

Vedclass Test Series

Exam Paper Generator

Online Exam Module