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(C) To determine if a complex is paramagnetic and low spin,we analyze the electronic configuration of the central metal ion and the nature of the liga

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$I$ and $IV$

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(C) To determine if a complex is paramagnetic and low spin,we analyze the electronic configuration of the central metal ion and the nature of the ligand:$(I) \, K_3[Fe(CN)_6]$: $Fe^{3+}$ is $3d^5$. $CN^-$ is a strong field ligand,causing pairing. Configuration: $t_{2g}^5 e_g^0$. It has one unpaired electron (paramagnetic) and is a low spin complex.$(II) \, [Ni(CO)_4]$: $Ni$ is $3d^8 4s^2$. $CO$ is a strong field ligand. Configuration: $3d^{10} 4s^0$. It has no unpaired electrons (diamagnetic).$(III) \, [Cr(NH_3)_6]^{3+}$: $Cr^{3+}$ is $3d^3$. Configuration: $t_{2g}^3 e_g^0$. It has three unpaired electrons (paramagnetic). Since it is a $d^3$ system,the concept of high/low spin does not apply.$(IV) \, [Mn(CN)_6]^{4-}$: $Mn^{2+}$ is $3d^5$. $CN^-$ is a strong field ligand,causing pairing. Configuration: $t_{2g}^5 e_g^0$. It has one unpaired electron (paramagnetic) and is a low spin complex.Thus,both $(I)$ and $(IV)$ are paramagnetic and low spin complexes.

Which of the following complex compound$(s)$ is/are paramagnetic and low spin?
$(I) \, K_3[Fe(CN)_6] \quad (II) \, [Ni(CO)_4] \quad (III) \, [Cr(NH_3)_6]^{3+} \quad (IV) \, [Mn(CN)_6]^{4-}$
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Which of the following complexes will show coordination isomerism?
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$B. [Co(NH_3)_6][Cr(CN)_6]$
$C. [Co(NH_3)_6][Co(CN)_6]$
$D. [Fe(NH_3)_6][Co(CN)_6]$
$E. [Co(NH_3)_6][Fe(CN)_6]$
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Which of the following complex compound$(s)$ is/are paramagnetic and low spin?$(I) \, K_3[Fe(CN)_6] \quad (II) \, [Ni(CO)_4] \quad (III) \, [Cr(NH_3)_6]^{3+} \quad (IV) \, [Mn(CN)_6]^{4-}$Choose the correct code: