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(A) $1$. Heating of $NH_4ClO_4$: $2 NH_4ClO_4 \xrightarrow{\Delta} N_2 \uparrow + Cl_2 \uparrow + 2 O_2 \uparrow + 4 H_2O$. This reaction produces $N_

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Heating of $NH_4ClO_4$

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(A) $1$. Heating of $NH_4ClO_4$: $2 NH_4ClO_4 \xrightarrow{\Delta} N_2 \uparrow + Cl_2 \uparrow + 2 O_2 \uparrow + 4 H_2O$. This reaction produces $N_2$ gas,not $NH_3$.$2$. Heating of $NH_4Cl$: $NH_4Cl \xrightarrow{\Delta} NH_3 \uparrow + HCl \uparrow$. This reaction liberates $NH_3$ gas.$3$. $(NH_4)_2CO_3 + 2 NaOH \longrightarrow 2 NH_3 \uparrow + Na_2CO_3 + 2 H_2O$. This reaction liberates $NH_3$ gas.$4$. $Li_3N + 3 H_2O \longrightarrow 3 LiOH + NH_3 \uparrow$. This reaction liberates $NH_3$ gas.Therefore,the heating of $NH_4ClO_4$ does not liberate $NH_3$ gas.

Which of the following combinations does not liberate $NH_3$ gas?

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