Which of the following can show geometrical i | vedclass

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(B) Geometrical isomerism in cyclic compounds arises when there are at least two substituents on different carbon atoms of the ring,such that the rota

Vedclass · Accepted Answer

$1-$bromo$-2-$chlorocyclopropane

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(B) Geometrical isomerism in cyclic compounds arises when there are at least two substituents on different carbon atoms of the ring,such that the rotation around the $C$-$C$ bonds is restricted and the relative positions of the substituents can be different (cis/trans).$(A)$ $3-$chlorocyclohexan$-1,1-$dimethyl: This molecule has two substituents on the same carbon ($C$-$1$),which prevents geometrical isomerism at that position. The chlorine at $C$-$3$ is a single substituent,so it cannot show cis/trans isomerism.$(B)$ $1-$bromo$-2-$chlorocyclopropane: This molecule has a substituent (Br) on $C$-$1$ and another substituent (Cl) on $C$-$2$. Because the ring restricts rotation,the Br and Cl can be on the same side (cis) or opposite sides (trans) of the ring plane. Thus,it shows geometrical isomerism.$(C)$ $1-$methylcyclobutane: This molecule has only one substituent on the ring. Geometrical isomerism requires at least two substituents on different carbons of the ring.Therefore,only $(B)$ can show geometrical isomerism.

Which of the following can show geometrical isomerism :-

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