Which of the following bromides is the major | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction involves the electrophilic addition of $HBr$ to the given polycyclic alkene. First,the proton $(H^+)$ from $HBr$ attacks one of the d

Vedclass · Accepted Answer

Vedclass · Answer

(D) The reaction involves the electrophilic addition of $HBr$ to the given polycyclic alkene. First,the proton $(H^+)$ from $HBr$ attacks one of the double bonds to form the most stable carbocation intermediate. In this structure,the formation of a tertiary $(3^\circ)$ carbocation is possible at the bridgehead position,which is more stable than secondary $(2^\circ)$ carbocations. Assuming no carbocation rearrangement,the bromide ion $(Br^-)$ then attacks this $3^\circ$ carbocation to form the final product. Based on the provided solution image,the product corresponds to the addition of $Br$ at the tertiary bridgehead carbon.

Which of the following bromides is the major product of the reaction shown below,assuming that there are no carbocation rearrangement?

Similar Questions

For the given reaction sequence,identify $C$ and $D$:
$3\text{-methylbut-1-ene}$ $\xrightarrow[(ii) NaBH_4]{(i) Hg(OAc)_2/H_2O} A$ $\xrightarrow{H^\oplus/\Delta} B$ $\xrightarrow{O_3/Zn/H_2O} C + D$

${\text{Glycerol}}$ $\xrightarrow{KHSO_4} (A)$ $\xrightarrow{LiAlH_4} (B)$; $(A)$ and $(B)$ are respectively:

At low temperatures,the slow addition of molecular bromine to $CH_2=CH-CH_2-C \equiv CH$ gives :-

How many products will be formed in the reaction shown below?
$CH_3-CH_2-C(CH_3)=C(CH_3)-CH_2-CH_3 + HBr \xrightarrow{R_2O_2} \text{Products}$

The reaction of propene with $HOCl$ proceeds via the addition of which of the following in the first step?

Vedclass Test Series

Exam Paper Generator

Online Exam Module