How many products will be formed in the reaction shown below?
$CH_3-CH_2-C(CH_3)=C(CH_3)-CH_2-CH_3 + HBr \xrightarrow{R_2O_2} \text{Products}$

  • A
    $2$
  • B
    $4$
  • C
    $3$
  • D
    $6$

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Reason $(R)$: $1-$bromopropane is the major product because it is formed through the stable carbocation.
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