Which of the following arrangements shows the | vedclass

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(B) To determine the paramagnetism,we look at the number of unpaired electrons in the ground state of each atom:$1. 	ext{Oxygen } (O): 1s^2 2s^2 2p^4

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$N > O > Al > Ca$

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(B) To determine the paramagnetism,we look at the number of unpaired electrons in the ground state of each atom:$1. 	ext{Oxygen } (O): 1s^2 2s^2 2p^4$. The $2p$ subshell has $2$ unpaired electrons.$2. 	ext{Nitrogen } (N): 1s^2 2s^2 2p^3$. The $2p$ subshell has $3$ unpaired electrons.$3. 	ext{Aluminum } (Al): [Ne] 3s^2 3p^1$. The $3p$ subshell has $1$ unpaired electron.$4. 	ext{Calcium } (Ca): [Ar] 4s^2$. All electrons are paired,so it is diamagnetic ($0$ unpaired electrons).Comparing the number of unpaired electrons: $N (3) > O (2) > Al (1) > Ca (0)$.Therefore,the correct order of decreasing paramagnetism is $N > O > Al > Ca$.

Which of the following arrangements shows the correct order of decreasing paramagnetism?

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