Which of the following are correct?(1) Electr | vedclass

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(C) $1$. In $d_{x^2-y^2}$ orbital,electrons are present along the $x$ and $y$ axes,so the electron density in the $XY$ plane is not zero.$2$. Accordin

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$2, 3, 4$

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(C) $1$. In $d_{x^2-y^2}$ orbital,electrons are present along the $x$ and $y$ axes,so the electron density in the $XY$ plane is not zero.$2$. According to the $(n+l)$ rule,the energy increases as the sum of $(n+l)$ increases.For $3p$,$(n+l) = 3+1 = 4$.For $2p$,$(n+l) = 2+1 = 3$.Thus,$3p$ has higher energy than $2p$.$3$. The number of angular nodes is equal to the azimuthal quantum number $l$.For $p$-orbitals,$l = 1$,so $3p_z$ has one angular node.$4$. The number of radial nodes is given by $(n-l-1)$.For $4f$,$n = 4$ and $l = 3$,so radial nodes $= 4-3-1 = 0$.

Set	$(n, l, m_l)$
$A$	$(3, 3, -3)$
$B$	$(3, 2, -2)$
$C$	$(2, 1, +1)$
$D$	$(2, 2, +2)$

Which of the following are correct?
$(1)$ Electron density in $XY$ plane for $d_{x^2-y^2}$ orbital is zero.
$(2)$ The energy of $3p$-orbital is higher than the energy of $2p$-orbital.
$(3)$ $3p_z$-orbital has one angular node.
$(4)$ $4f$-orbital has no radial node.

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$A$ $(3, 3, -3)$

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Which of the following are correct?$(1)$ Electron density in $XY$ plane for $d_{x^2-y^2}$ orbital is zero.$(2)$ The energy of $3p$-orbital is higher than the energy of $2p$-orbital.$(3)$ $3p_z$-orbital has one angular node.$(4)$ $4f$-orbital has no radial node.