Which of the following aqueous solutions will | vedclass

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(C) The elevation in boiling point is given by the formula: $\Delta T_b = i \cdot K_b \cdot m$. Since $K_b$ is constant for the same solvent (water) a

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$0.01 \ M \ Na_2SO_4$

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(C) The elevation in boiling point is given by the formula: $\Delta T_b = i \cdot K_b \cdot m$. Since $K_b$ is constant for the same solvent (water) and assuming molality $m \approx M$,the boiling point depends on the product of the van't Hoff factor $(i)$ and molarity $(M)$. Calculating $i 	imes M$ for each: $A$: Urea is a non-electrolyte,$i = 1$. $1 	imes 0.01 = 0.01$. $B$: $KNO_3 ightarrow K^+ + NO_3^-$,$i = 2$. $2 	imes 0.01 = 0.02$. $C$: $Na_2SO_4 ightarrow 2Na^+ + SO_4^{2-}$,$i = 3$. $3 	imes 0.01 = 0.03$. $D$: Glucose $(C_6H_{12}O_6)$ is a non-electrolyte,$i = 1$. $1 	imes 0.015 = 0.015$. Since the product $i 	imes M$ is highest for $Na_2SO_4$,it will exhibit the highest boiling point.

Which of the following aqueous solutions will exhibit the highest boiling point?

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