Which of the following aqueous solutions of s | vedclass

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(C) $NaCl$ is a salt of a strong acid $(HCl)$ and a strong base $(NaOH)$,so its aqueous solution is neutral $(pH = 7)$.$CH_3COONH_4$ is a salt of a we

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$Na_2CO_3$

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(C) $NaCl$ is a salt of a strong acid $(HCl)$ and a strong base $(NaOH)$,so its aqueous solution is neutral $(pH = 7)$.$CH_3COONH_4$ is a salt of a weak acid $(CH_3COOH)$ and a weak base $(NH_4OH)$,so its aqueous solution is approximately neutral $(pH \approx 7)$.$Na_2CO_3$ is a salt of a weak acid $(H_2CO_3)$ and a strong base $(NaOH)$,so it undergoes anionic hydrolysis to form a basic solution $(pH > 7)$.$NH_4Cl$ is a salt of a strong acid $(HCl)$ and a weak base $(NH_4OH)$,so it undergoes cationic hydrolysis to form an acidic solution $(pH Therefore,$Na_2CO_3$ has the highest $pH$ value.

Which of the following aqueous solutions of salts will have the highest $pH$ value?

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