Which of the following aqueous solutions havi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The elevation in boiling point is given by the formula $\Delta T_b = i 	imes K_b 	imes m$. Since the molality $(m)$ and the ebullioscopic consta

Vedclass · Accepted Answer

$AlCl_3$

Vedclass · Answer

(C) The elevation in boiling point is given by the formula $\Delta T_b = i 	imes K_b 	imes m$. Since the molality $(m)$ and the ebullioscopic constant $(K_b)$ are the same for all solutions,the elevation in boiling point depends directly on the van't Hoff factor $(i)$.For complete dissociation:$KCl ightarrow K^+ + Cl^-$ $(i = 2)$$NaCl ightarrow Na^+ + Cl^-$ $(i = 2)$$AlCl_3 ightarrow Al^{3+} + 3Cl^-$ $(i = 4)$$BaCl_2 ightarrow Ba^{2+} + 2Cl^-$ $(i = 3)$Since $AlCl_3$ has the highest van't Hoff factor $(i = 4)$,it will exhibit the maximum boiling point elevation.

Which of the following aqueous solutions having same molality exhibits maximum boiling point elevation? (Assume complete dissociation)

Similar Questions

The freezing point (in ${}^{\circ}C$) of a solution containing $0.1 \ g$ of $K_3[Fe(CN)_6]$ (Mol. Wt. $329$) in $100 \ g$ of water $(K_f = 1.86 \ K \ kg \ mol^{-1})$ is

$A$ $0.1 \ mol$ of a binary electrolyte undergoes complete dissociation in $250 \ g$ of a protic solvent. If the elevation in boiling point is $1.5 \ K$,the molal elevation constant $(K_b)$ is ............. $K \ kg \ mol^{-1}$.

Which of the following solutions has an osmotic pressure nearest to that of an equimolar solution of $K_4[Fe(CN)_6]$?

What would the boiling point elevation of $0.1 \ m$ $KNO_3$ be equal to?

Assuming $100\%$ ionization,the correct order of freezing point for the following solutions is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module