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(D) In an $E_2$ reaction,a base removes a $\beta$-hydrogen atom anti-periplanar to the leaving group $(-Cl)$.$A$: $1$-chloro-$1$-methylcyclohexane has

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$1-$chloro$-4-$methylcyclohexane

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(D) In an $E_2$ reaction,a base removes a $\beta$-hydrogen atom anti-periplanar to the leaving group $(-Cl)$.$A$: $1$-chloro-$1$-methylcyclohexane has two types of $\beta$-hydrogens,leading to two different alkenes (exocyclic and endocyclic).$B$: $1$-chloro-$2$-methylcyclohexane has multiple $\beta$-hydrogens,leading to a mixture of isomers.$C$: $1$-chloro-$3$-methylcyclohexane also yields a mixture of isomers due to different $\beta$-hydrogens.$D$: $1$-chloro-$4$-methylcyclohexane is symmetric. The $\beta$-hydrogens at the $C_3$ and $C_5$ positions are equivalent,and the $\beta$-hydrogens at the $C_2$ and $C_6$ positions are equivalent. However,due to the symmetry of the molecule,elimination leads to a single product: $4$-methylcyclohexene.

Which of the following alkyl halides gives only one product (excluding stereoisomers) when undergoing an $E_2$ reaction? $(E_2 = \text{elimination bimolecular})$

Similar Questions

The rate of $S_N2$ reaction will be negligible in:

$CH_3-C(CH_3)=CH-CH_2-CH_2-Cl \xrightarrow[CaCO_3]{H_2O} (X)$
The major product $(X)$ of the above reaction is:

Which of the following is least reactive towards $S_N2$ reaction?

Predict the order of reactivity of the following compounds in $S_N1$ reaction :
$(I)$ $CH_3-CH_2-CH(Br)-CH_3$
$(II)$ $(CH_3)_2CH-CH_2-Br$
$(III)$ $(CH_3)_3CBr$

Which one of the following is the best catalyst for the reaction shown below?
$CH_3(CH_2)_8CH_2Br \xrightarrow[benzene]{KCN} CH_3(CH_2)_8CH_2CN$

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